We know that the moviment of acceleration due the gravity accomplish the following rules:
H = Vi * T + 1/2 * g * T^2 and V = Vi + g* T
where: H is height, Vi is initial speed, T is time and g is gravity acceleration
Then, as we drop off the stone, means initial speed is zero, so we can calculate first the time to hit the ground
V = Vi + g * T => 112 = 0 + 32 * T => T = 3.5 seconds
Within that time the height dropped by the stone will be:
H = Vi * T + 1/2 * g * T^2 = 0 * 3.5 + 1/2 * 32 * 3.5^2 = 196 ft
So we conclude that the height of the cliff is 196 feet.
