An isosceles triangle has a base length 15. the length of each the other two equal sides is an integer. what is the shortest possible length of these other two sides
The lowest it can be is 8. The sum of two sides of a triangle has to be greater than the remaining side, and since 8 + 8 = 16 which is greater than 15, this would be the answer. (It cannot be 7 since 7 + 7 equals 14) I hope this helps. YOU'RE WELCOME :D