The area of a rectangle is (x^4+4x^3+3x^2-4x-4),and the length of the rectangle is (x^3+5x^2+8x+4). if the area = length x width, what is the width of the rectangle

Respuesta :

W = A/L
W = (x^4+4x^3+3x^2-4x-4) / (x^3+5x^2+8x+4)
W = x - 1

Answer: x-1

Step-by-step explanation: if the area of a rectangle is the length multiplied by the width, the width would be the area divided by the length:

A=L*W

W=A/L

substituting the given expressions:

[tex]W=\frac{x^{4}+4x^{3}+3x^{2}-4x-4   }{x^{3} +5x^{2}+8x+4 }[/tex]

now dividing the polynomials we have that the first term of the quotient is given by:

[tex]\frac{x^{4} }{x^{3} } =x[/tex]

when multiplying this term by the divisor and substracting the result from the dividend we are left with the following polynomial:

[tex]-x^{3}-5x^{2}-8x-4[/tex]

the second term of the quotient is given by:

[tex]\frac{-x^{3} }{x^{3} } =-1[/tex]

when multiplying by the divisor and substracting it from the divident the remainder is zero.

so the answer is W=x-1