Edy has $450 in her savings account. She deposits $40 each month. Juan has $975 in his checking account. He writes a check for $45 each month for his cell phone bill. He also writes a check for $20 each month for his water bill. After how many months will Edy and Juan have the same amount of money in their accounts?

Respuesta :

Answer: 5 Months


Step-by-step explanation:

$450 + $40x = $975-$45x-$20x  (combine like terms)

450 + 40x = 975 - 65x (perform inverse operations to get only the variable on one side, what is done to one side must be done to the other)

450 + 40x + 65x = 975 - 65x + 65x

450 - 450 + 105x = 975 - 450

105x = 525 (divide both sides by 105)

x=5

Algebraic equations are equations that have unknown variables in them

Edy and Juan will have the same amount of money in their accounts after 21 months.

Let the number of months deposits is made into their account be represented as: m

Edy has $450 in her savings account. She deposits $40 each month.

The algebraic equation for Edy =

$450 + $40 x m

= 450 + 40m .........Equation 1

Juan has $975 in his checking account. He writes a check for $45 each month for his cell phone bill. He also writes a check for $20 each month for his water bill.

The algebraic equation for Juan is given as:

$975 + ($45 + $20) x m

975 + 65m ----------Equation 2

For Edy and Juan to have the same amount of money in their accounts,

We equate the equations to each other

Equation 1 = Equation 2

450 + 40m = 975 + 65m

Collect like terms

65m - 40m = 975 - 450

25m = 525

Divide both sides by 25

25m/25 = 525/25

m = 525/25

m = 21

Therefore, Edy and Juan will have the same amount of money in their accounts after 21 months.

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