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When the product of 6 and the square of a number is increased by 5 times the number, the result is 4. Which equation represents this situation? 6x2 + 5x - 4 = 0 6x2 + 5x + 4 = 0 62x + 5 + x = 4 6 + x2 + 5x = 4

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[tex]6{x}^{2} + 5x = 4[/tex]
[tex]6 {x}^{2} + 5x - 4 = 0[/tex]

Answer:

The equation that represents this situation is given by:

                           [tex]6x^2+5x-4=0[/tex]

Step-by-step explanation:

Let " x " be any number.

Square of this number is: x²

and the product of 6 and square of a number is given by: 6x²

Now if this quantity is increased by 5 times the number; then the result is 4.

( 5 times the number x is given by: 5x )

This means that the expression could be given by:

                 [tex]6x^2+5x=4[/tex]

On subtracting both side of the equality by 4 we obtain the equation as:

                      [tex]6x^2+5x-4=0[/tex]

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