A 8.40 kg mass suspended from a spring with spring constant, k = 875.0 n/m, extends it to a total length of 0.250 m. find the total length of the spring when a 17.20 kg mass is suspended from it.
In the first scenario, since the spring extends upto 0.25 metre, the body must be at equilibrium at this point. That implies, ma = kx a = 26 m/s^2 In the second scenario, (at equilibrium) ma = kx (17.2)(26) = 875(x) x = 0.511m
