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Part a - calculate the value of q what is the value of q when the solution contains 2.00×10−3 m ca2+ and 3.00×10−2m so42−? express your answer numerically.

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W0lf93
Answer: [Pb2+] > (1.17x10^-5)/(1.00x10^-2)^2 = 0.117 M

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