Answer:
Given Equation : 1 + 2b - 13 = 12 - 4b - 2b
To write: Correct Steps to solve for b
In Step 1: We simplify constant in LHS.
⇒ 2b + ( 1 - 13 ) = 12 - 4b - 2b
⇒ 2b + ( -12 ) = 12 - 4b -2b
⇒ 2b - 12 = 12 - 4b - 2b
In Step 2: We simplify variable part in RHS
⇒ 2b - 12 = 12 + ( -4b -2b )
⇒ 2b - 12 = 12 + ( -6b )
⇒ 2b - 12 = 12 - 6b
In Step 3: We transpose 6b of RHS to LHS
⇒ 2b - 12 + 6b = 12
In Step 4: Now simplify variable in LHS
⇒ 2b + 6b - 12 = 12
⇒ 8b - 12 = 12
In Step 5: Transpose 12 to RHS
⇒ 8b = 12 + 12
In Step 6: Simplify constants in RHS
⇒ 8b = 24
In Step 7 transpose 8 to RHS
[tex]\implies\:b\,=\,=\frac{24}{8}[/tex]
In Step 8: Simplify RHS
⇒ b = 3
