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(06.02 MC)
The equation of line EF is y = 2x + 1. Write an equation of a line parallel to line EF in slope-intercept form that contains point (0, 2). (5 points)


y = 2x − 4
y = 2x + 2
y = negative 1 over 2 x − 4
y = negative 1 over 2 x + 2

Respuesta :

mathstudent55
y = mx + b is the slope-intercept form of the equation of a line.
m = slope, and b =y-intercept

The equation for line EF, y = 2x + 1, is in slope-intercept form.
The slope, m, is 2.

Parallel lines have equal slopes.
The line we are looking for also has slope = m = 2.

y = mx + b

y = 2x + b

We need to find b. We can use the given point, (0, 2), for x and y and solve for b.

y = 2x + b

2 = 2 * 0 + b

2 = b

b = 2

Now we replace b with 2.

y = 2x + 2

Answer: The equation of the parallel line is y = 2x + 2.
facundo3141592

The line equation that we want to find is:

y = 2*x + 2

How to write parallel lines?

A general linear equation is:

y = a*x + b

Where a is the slope and b is the y-intercept.

We know that two lines are parallel if the lines have the same slope but different y-intercept.

So if we want our line to be parallel to EF, we must have something like:

y = 2*x + c

To find the value of c, we use the fact that our line contains the point (0, 2), then we have:

2 = 2*0 + c

2 = c

So the line is:

y = 2*x + 2.

If you want to learn more about linear equations, you can read:

https://brainly.com/question/4074386

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