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Calculate the solubility (in m) of cobalt(ii) hydroxide, co(oh)2(s) in h2o. ksp = 3.60×10-16 at a specific temperature. what is the ph

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Kalahira
The redox reaction is given as CO2+ + 2OH- gives Co(OH)2 The Ksp expression is given as [Co2+][OH2-] Let [CO2+] =X and 2[OH2-] =2X Then X *2X^2 = 3.6 * 10^(-6). Multiplying the ksp expressions It follows that 2X^3 = 3.6 * 10^(-6). X^3 = 3.6 * 10^(-6)/2 = 0.089/2 = 0.0466.

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