Answer:
Sine
Step-by-step explanation:
We are given that a triangle XMI in which
[tex]MI=20 units[/tex]
[tex]XI=z[/tex]
[tex]\angle MXI=28^{\circ}[/tex]
We have to find which trigonometric ratio would use to solve for z.
We know that
[tex]Sin\theta=\frac{Perpendicular\;side}{hypotenuse}[/tex]
[tex]cosin\theta=\frac{base}{Hypotenuse}[/tex]
[tex]tan\theta=\frac{Perpendicular\;side}{base}[/tex]
We have , Perpendicular side =MI=20 units
Hypotenuse,XI=z
Base=XM
[tex]sin28^{\circ}=\frac{20}{z}[/tex]
[tex]z=\frac{20}{sin28^{\circ}}[/tex]
Hence, we would use sine to solve for z.
