A. Determine the area of a circle with 1.15 cm diameter.
A = πr²
Substituting,
A = π(1.15 cm/100 cm)² = 4.15 m²
Multiply this to the given shearing stress.
shearing force = (4 x 10^8 N/m²)(4.15 m²)
shearing force = 1.66 x 10^9 N
b. Determine the surface area of the cylinder that is made upon boring the hole in steel plate.
A = 2πrh
Substituting,
A = 2π(0.0145m)(0.0086)
A = 7.84 x 10^-4 m²
Multiplying with shear stress,
shear force = 3.13 x 10^5 N
