The mass of 2.6 mol of Lithium bromide is 225.797 g.
The Lithium bromide has the molecular formula: LiBr.
The molecular mass of the LiBr will be the sum of the molar mass of Li and Br.
The molecular mass of LiBr = molar mass of Li + molar mass of Br.
The molar mass of Li = 6.941 u
The molar mass of Br = 79.904 u
The molecular mass of LiBr = 6.941 u + 79.904 u
The molecular mass of LiBr = 86.845 g/mol.
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
weight = moles [tex]\times[/tex] molecular weight
weight of LiBr = 2.6 [tex]\times[/tex] 86.845 g
Weight of 2.6 moles LiBr = 225.797 g.
The mass of 2.6 mol of Lithium bromide is 225.797 g.
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