Respuesta :
You can do it in two ways:
1) solve the equation
2) replace the values given in the equation.
To solve the equation you can use the quadratic formula,
x = (- b +/- √[b^2 - 4ac] / (2a)
=> x = { - (-8) +/- √ [ (8^2) - 4(3)(4) ] } / (2*3) = { 8 +/- √ [64 - 48] } (6)
x = { 8+/- √16 } / (6) = { 8 +/- 4 } / 6
x = (8+4) / 6 and x = (8 - 4)/ 6
x - 12 / 6 and x = 4 / 6
x = 2 and x = 2/3
Answer: option A. x = 2 and x = 2/3
1) solve the equation
2) replace the values given in the equation.
To solve the equation you can use the quadratic formula,
x = (- b +/- √[b^2 - 4ac] / (2a)
=> x = { - (-8) +/- √ [ (8^2) - 4(3)(4) ] } / (2*3) = { 8 +/- √ [64 - 48] } (6)
x = { 8+/- √16 } / (6) = { 8 +/- 4 } / 6
x = (8+4) / 6 and x = (8 - 4)/ 6
x - 12 / 6 and x = 4 / 6
x = 2 and x = 2/3
Answer: option A. x = 2 and x = 2/3
3x^2 - 8x + 4 = 0
3x^2 - 6x - 2x + 4 = 0
3x(x - 2) - 2(x - 2) = 0
(3x - 2)(x - 2) = 0
x = 2/3 and x = 2
Its A
3x^2 - 6x - 2x + 4 = 0
3x(x - 2) - 2(x - 2) = 0
(3x - 2)(x - 2) = 0
x = 2/3 and x = 2
Its A