Answer: [tex]0.24cal/g^0C[/tex]
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat absorbed= 569 calories
m= mass of substance = 155 g
c = specific heat capacity = ?
Initial temperature = [tex]T_i[/tex] = 25.0°C
Final temperature = [tex]T_f[/tex] = 40.0°C
Change in temperature ,[tex]\Delta T=T_f-T_i=(40-25)^0C=15^0C[/tex]
Putting in the values, we get:
[tex]569=155\times c\times 15^0C[/tex]
[tex]c=0.24cal/g^0C[/tex]
The specific heat of the substance is [tex]0.24cal/g^0C[/tex]
