Respuesta :
the remaining value= the initial value × (1/2)^(t/T), t is the number of years, T is half life.
So D is the right answer.
So D is the right answer.
The amount of isotope remaining after t days is [tex]A=100(\frac{1}{2} )^\frac{t}{14.26}[/tex]
Half life is the amount of time that it takes a substance to decay to half of its original value. It is given by:
[tex]N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} }[/tex]
Where N(t) is the amount of substance remaining, N₀ is the initial amount, t is the time and t₁₂ is the the half life.
Given that:
- Half life = 14.26 days, initial amount = 100
Hence:
[tex]A=100(\frac{1}{2} )^\frac{t}{14.26}[/tex]
The amount of isotope remaining after t days is [tex]A=100(\frac{1}{2} )^\frac{t}{14.26}[/tex]
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