Respuesta :
Answer:
1.
Let the length be = l
Let the width be = w
The length of a rectangle is three times its width. So, [tex]l=3w[/tex]
If the perimeter is at most 112 centimeters, means it should exceed 112 cm.
We can define these as : [tex]2l+2w \leq 112[/tex]
Substituting l = 3w
[tex]2(3w)+2w \leq 112[/tex] (option B)
2.
We have to solve the above equation here.
[tex]2(3w)+2w \leq 112[/tex]
=> [tex]6w+2w \leq112[/tex]
=> [tex]8w \leq112[/tex]
=> [tex]w \leq14[/tex]
So, width can be at most 14 cm. (option C)
3.
Eduardo spent $7500 to obtain his merchandise, and it costs him $300 per week for general expenses.
He earns $850 per week in sales.
Let the number of weeks needed be = w
So, the inequality here becomes:
[tex]850w>7500+300w[/tex] (option B)
4.
Reiko spent $5200 to obtain her merchandise, and it costs her $550 per week for general expenses.
She earns $900 per week in sales.
Let the weeks be w
So, inequality here becomes;
[tex]900w>5200+550w[/tex]
Solving this we get;
[tex]900w-550w>5200[/tex]
[tex]350w>5200[/tex]
[tex]w>14.85[/tex]
So, the minimum number of weeks needed to get profit will be 15 weeks (option A)
5.
Let Jenny's age be J
Let Sue's age be S
Jenny is eight years older than twice her cousin Sue’s age.
So we get, [tex]J=8+2S[/tex] ....(1)
The sum of their ages is less than 32. We get [tex]J+S<32[/tex] ....(2)
Substituting J=8+2S in (2)
[tex]8+2S+S<32[/tex]
[tex]3S+8<32[/tex]
[tex]3S<32-8[/tex]
[tex]3S<24[/tex]
[tex]S<8[/tex]
We get Sue's age =7 (option A)