Assuming a linear function:
The slope of the graph is:
rise/run = (62-53) / (6-3) = 9/3 = 3
Plugging in a point and the slope:
y = 3x + b Plug in (3,53) for (x,y)
53 = 3*3 + b Subtract 9 from both sides
44 = b
Therefore:
y = 3x + 44
In Standard Form:
y - 3x = 44
In order to graph for the first seven hours, or any amount of time greater than zero, you would start at the point (0, 44) and draw a line moving rightward (1st quadrant of the graph) with a slope of 3.