With a point (h,k) an equation of a line in point-slope form is y-k=m(x-h).
A(-2, -1)= (X1,Y1)
B(6,5)= (X2,Y2)
Slope = ((Y2-Y1)/(X2-X1))
m= ((5-(-1))/(6-(-2))= (5+1)/(6+2)= 6/8= 3/4
m= 3/4
ANSWER:
When using point B, (6,5) = (h,k)
y-k=m(x-h)
y-5=(3/4)(x-6)
None of the equations using point A's cooridinates for h and k would work because A(-2,-1) has negative values. These negative would alter the subtraction in the equation to addition for example a correct equation for point A would be: y+1=(3/4)(x+2).
The other equation with B's coordinates swapped h and k's places in the equation so it is also in correct.
Hope this helped!
