Answer:
Step-by-step explanation:
The given expression is given as :
[tex]\frac{4\sqrt{6}}{3\sqrt{2}} [/tex]
To solve the expression we rationalise the denominator as it is irrational by multiplying both numerator and denominator by [tex]\sqrt{2}[/tex]
[tex]\frac{4\sqrt{6}}{3\sqrt{2}}\times\frac{\sqrt{2}}{\sqrt{2}} [/tex]
On multiplying the tems inside the roots we get
[tex]\frac{4\sqrt{12}}{3\sqrt{4}} [/tex]
As factor of 12 are [tex] =2\times2\times3[/tex]
On solving the square root we get
[tex]\frac{8\sqrt{3}}{6} [/tex]
As both the numbers 8 and 6 are divisible by 2 on solving we get
[tex]\frac{4\sqrt{3}}{3} [/tex]
is the final answer
Hope this will help
