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The answer is 720.68, but to 3 sig. figs it would be 721. You get this by:

3.91x10^24 (1mol/ 6.02x10^3 molecules) (110.96/ 1mol)= 720.68

Hope that helps!

Answer:

Mass of [tex]3.91\times 10^{24}[/tex] number of [tex]SeO_{2}[/tex] molecules is 720.3g

Explanation:

Mass of 1 mol of [tex]SeO_{2}[/tex] is 110.96 g

We know, 1 mol of molecule = [tex]6.023\times 10^{23}[/tex] number of molecules

So, mass of [tex]6.023\times 10^{23}[/tex] number of [tex]SeO_{2}[/tex] molecules is 110.96 g

Hence mass of [tex]3.91\times 10^{24}[/tex] number of [tex]SeO_{2}[/tex] molecules = [tex]\frac{110.96\times 3.91\times 10^{24}}{6.023\times 10^{23}}g=720.3g[/tex]

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