Answer:
The probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner is [tex]\frac{3}{10}[/tex]
Step-by-step explanation:
To find : What is the probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner that is divided into 15 equal sectors numbered 1 through 15?
Solution :
In flipping a coin outcomes are {H,T} = 2
Favorable outcome of getting head on a coin {H}=1
The probability of flipping heads on a coin is
[tex]P(H)=\frac{1}{2}[/tex]
Spinner that is divided into 15 equal sectors numbered 1 through 15.
Favorable outcome of getting a number greater than 6 {7,8,9,10,11,12,13,14,15}=9
The probability of spinning a number greater than 6 is
[tex]P(S)=\frac{9}{15}[/tex]
[tex]P(S)=\frac{3}{5}[/tex]
Now, The probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner is given by,
[tex]P(H\text{ and } S)=P(H)\times P(S)[/tex]
[tex]P(H\text{ and }S)=\frac{1}{2}\times\frac{3}{5}[/tex]
[tex]P(H\text{ and }S)=\frac{3}{10}[/tex]
Therefore, The probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner is [tex]\frac{3}{10}[/tex]
