Respuesta :
There are 1.923×10^23 formula units in 30.4g mgcl2
molar mass of mgcl2= 95.211g/mol
magnesium= 24.305g/mol
chlorine= 35.45g/mol times 2
24.305+(35.45*2)= 95.211g/mol
sample divided by molar mass times Avogadro's number gives u the formula units
30.4÷ 95.211= .31929
.3193*6.022=1.9288
molar mass of mgcl2= 95.211g/mol
magnesium= 24.305g/mol
chlorine= 35.45g/mol times 2
24.305+(35.45*2)= 95.211g/mol
sample divided by molar mass times Avogadro's number gives u the formula units
30.4÷ 95.211= .31929
.3193*6.022=1.9288
Answer: The number of formula units in the given amount of magnesium chloride is [tex]1.93\times 10^{23}[/tex]
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of magnesium chloride = 30.4 g
Molar mass of magnesium chloride = 95.2 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of magnesium chloride}=\frac{30.4g}{95.2g/mol}=0.32mol[/tex]
Formula units is defined as lowest whole number ratio of ions in an ionic compound. It is calculate by multiplying the number of moles by Avogadro's number which is [tex]6.022\times 10^{23}[/tex]
We are given:
Number of moles of magnesium chloride = 0.32 moles
Number of formula units = [tex]0.32\times 6.022\times 10^{23}=1.93\times 10^{23}[/tex]
Hence, the number of formula units in the given amount of magnesium chloride is [tex]1.93\times 10^{23}[/tex]