By applying the concepts of polynomials and the quadratic equations, the complex number 1 ± i √7 is a solution of the quadratic equation x² - 2 · x = - 8.
In this question we have a quadratic equation, which has to rearranged into standard form and solved analytically by the quadratic formula. The standard form and the quadratic formula are shown below:
a · x² + b · x + c = 0 (1)
[tex]x = \frac{-b \pm \sqrt{b^{2}-4\cdot a \cdot c}}{2\cdot a}[/tex] (2)
Now we proceed to find the roots of the quadratic equation:
x² - 2 · x + 8 = 0
[tex]x = \frac{2 \pm \sqrt{(-2)^{2}-4\cdot (1)\cdot (8)}}{2\cdot (1)}[/tex]
x = 1 ± i 0.5 √28
x = 1 ± i √7
By applying the concepts of polynomials and the quadratic equations, the complex number 1 ± i √7 is a solution of the quadratic equation x² - 2 · x = - 8.
To learn more on quadratic equations: https://brainly.com/question/2263981
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