Respuesta :
Both molecules are long chain based polymers of carbohydrates. This can easily be told based on the fact that the 3 main elements that make up a sugar are present C , H and O.
This would be C11H12O11 in terms of simple empirical formula.
This would be C11H12O11 in terms of simple empirical formula.
Answer:
[tex]C_{22} H_{24} O_{2}[/tex]= Lipid
[tex]C_{22} H_{24} O_{22}[/tex] = Carbohydrate
Explanation:
The given compounds have molecular formulas:
Compound 1: [tex]C_{22} H_{24} O_{2}[/tex]
Compound 2: [tex]C_{22} H_{24} O_{22}[/tex]
Both compounds are composed of carbon (C), hydrogen (H) and oxygen (O) with the same C:H ratios but different O content
In compound 2, the C:H:O ratio is 1:2:1 i.e. the C and O are present in equivalent amounts. This is characteristic of carbohydrates.
In compound 1, the C:H:O ratio is 1:2:(<1). The 'O' content is less than 'C' which is characteristic of lipids.