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Consider the chemical equation. 2NBr3 + 3NaOH mc008-1.jpg N2 + 3NaBr + 3HOBr If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?

Respuesta :

The correct answer o your amazing question is NBr3
Dejanras

Answer is: NBr₃ is the excess reactant.

Balanced chemical reaction: 2NBr₃ + 3NaOH → N₂ + 3NaBr + 3HBrO.

n(NBr₃) = 40 mol; amount of substance.

n(NaOH) = 48 mol.

From chemical reaction: n(NBr₃) : n(NaOH) = 2 : 3.

40 mol : n(NaOH) = 2 : 3.

n(NaOH) = 60 mol; for 40 moles of NBr₃, 60 moles of NaOH is needed, because there is only 48 moles, not all NBr₃ will react (onl 32 moles, 16 moles are excess).