Which of the following describes the solution to the equation √c^2+2c-4=√1-2c?
– 5 is an extraneous solution, and 1 is a true solution.
– 5 is a true solution, and 1 is an extraneous solution.
Both –5 and 1 are true solutions.
Both –5 and 1 are extraneous solutions.
√c^2+2c-4=√1-2c raising both members to the square c^2+2c-4=1-2c rewriting c^2+4c-5=0 factoring (c+5)*(c-1)=0 the solutions for this case re c=-5 c=1 the answer is Both –5 and 1 are true solutions
