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Answer is: specific gravity of glucose is 1,02.
d(glucose) = 1,02 g/ml.
d(water) = 1,00 g/ml.
Specific gravity of glucose = density of glucose ÷ density of water.
Specific gravity of glucose = 1,02 g/ml ÷ 1,00 g/ml.
Specific gravity of glucose = 1,02.
Specific gravity is the ratio of the density of a substance (in this case glucose) to the density of a reference substance (water).

Answer: The specific gravity of glucose solution is 1.02

Explanation:

The relationship between specific gravity and density of a substance is given as:

[tex]\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}[/tex]

We are given:

Density of glucose solution = 1.02 g/mL

Density of water = 1.00 g/mL

Putting values in above equation we get:

[tex]\text{Specific gravity of glucose solution}=\frac{1.02g/mL}{1.00g/mL}\\\\\text{Specific gravity of glucose solution}=1.02[/tex]

Hence, the specific gravity of glucose solution is 1.02