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A ball is thrown into the air with an upward velocity of 24 ft/s. Its height h in feet after t seconds is given by the function h = –16t2 + 24t + 7. a. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. b. What is the ball’s maximum height?

Respuesta :

briyonalittle19
dh/dt = -32t + 24
-32t + 24 = 0 when maximum
32t = 24
t = 24/32
t = 3/4

To find the maximum height just substitute "t" in

h = -16 (9/16) + 24(3/4) + 7
h = -9 + 18 + 7
h = 16ft

Answer:

16ft

Step-by-step explanation:

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