Respuesta :
Answer: 0.6525 moles
Explanation:
Molarity : It is defined as the number of moles of solute present per Liter of the solution.
Formula used :
[tex]Molarity=\frac{n}{V_s}[/tex]
where,
n= moles of solute
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]V_s[/tex] = volume of solution in L
Now put all the given values in the formula of molarity, we get
[tex]0.75M=\frac{n\times 1000}{870ml}[/tex]
[tex]n=0.6525moles[/tex]
Therefore, the moles of [tex]CO_4[/tex] will be 0.6525.
Answer : The moles of [tex]CO_4[/tex] are 0.65 moles.
Explanation : Given,
Volume of solution = 870 mL = 0.870 L (1 L = 1000 mL)
Molarity = 0.75 M
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
In this question, the solute is [tex]CO_4[/tex].
Now put all the given values in this formula, we get:
[tex]0.75M=\frac{\text{Moles of solute}}{0.870L}[/tex]
[tex]\text{Moles of solute}=0.75M\times 0.870L[/tex]
[tex]\text{Moles of solute}=0.65mole[/tex]
Therefore, the moles of [tex]CO_4[/tex] are 0.65 moles.
