Respuesta :

[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$5000\\ r=rate\to 3.8\%\to \frac{3.8}{100}\to &0.038\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\to &1\\ t=years\to &3 \end{cases} \\\\\\ A=5000\left(1+\frac{0.038}{1}\right)^{1\cdot 3}\implies A=5000(1.038)^3[/tex]