contestada

the first aircraft has 85 more seats than the second aircraft. the third aircraft has 51 fewer seats than the second aircraft. if their a total of seats is 436, find the number of seats of each aircraft

Respuesta :

Lets start with the 2nd flight. 

Number of seats on the 2nd plane: X
Number of seats on the 1st plane : X+85
Number of seats on the 3rd plane: X-51

Total number of seats = 436. 
436= (x)+(x+85)+(x-51)
436= 3x+34
436-34=3x
402=3x
402/3=x = 134- on 2nd plane. 
                 134+85= 219 on 1st plane.
                 134-51 = 83 on the 3rd plane.

Quick Check
134+219+83= 436
436=436! So, our answer is correct!




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