The heavyweight boxing Champion of the world punches a sheet of paper in midair, bringing it from rest up to a speed of 24.0m/s In 0.054s. The mass of the paper is 0.003 kg. Find the force of the punch on the paper.

Respuesta :

Force is the rate at which momentum changes with respect to time.

Let [tex] v_i [/tex] be initial velocity. [tex] v_f [/tex] be final velocity. [tex] m [/tex] be the mass. [tex] \Delta [/tex] represents change.

Here change in momentum is [tex] \Delta p=m \Delta v\\
\Delta p=m (v_f-v_i)\\
\Delta p=0.003 (24-0)\\
\Delta p=0.072
[/tex]

Since the rate of change of momentum is force,

[tex] F=\frac{\Delta p}{\Delta t} \\
F=\frac{0.072}{0.054} \\
F=1.333 m/s [/tex]