Answer:
There are 7 coins of quarters , 12 coins of dimes and 16 coins of nickels .
Step-by-step explanation:
Mukul has $3.75
1 dollar = 100 cents
3.75 dollar = 375 cents
Let he has x coins of quarters
Since we are given that he has five more dimes than quarters.
So, Dimes = x+5
Since we are given that he has nine more nickels than quarters .
So, nickels = x+9
Now 1 quarter = 25 cents
So, x quarter = 25 x cents
1 dime = 10 cents
So, (x+5) dimes = 10(x+5) cents
1 nickel = 5 cents
So, (x+9) nickels = 5(x+9) cents.
Since he had 375 cents in total .
[tex]\Rightarrow 25 x+ 10(x+5) +5(x+9)=375[/tex]
[tex]\Rightarrow 25 x+ 10x+50 +5x+45=375[/tex]
[tex]\Rightarrow 40 x+95=375[/tex]
[tex]\Rightarrow 40 x=375-95[/tex]
[tex]\Rightarrow 40 x=280[/tex]
[tex]\Rightarrow x=\frac{280}{40}[/tex]
[tex]\Rightarrow x=7[/tex]
Thus there are 7 coins of quarters
Coins of dimes = x+5=7+5=12
Coins of nickels = x+9=7+9 =16
Hence there are 7 coins of quarters , 12 coins of dimes and 16 coins of nickels .
