Answer:
The correct answer is that the pressure of the gas increases by a factor of four.
Explanation:
On the basis of the Gay-Lussac's law, the pressure of a given concentration of gas held at constant volume is directly equivalent to the Kelvin temperature.
i.e, p1/T1 = p2/T2, that is, as the temperature rises, the pressure also elevates and vice versa.
Let us consider an example, T1 = 1, T2 = 4, p1 = 1 and p2 is unknown. Thus, according to Gay-Lussac's law:
p2 = p1 / T1 × T2
p2 = 1 / 1 × 4
p2 = 4
Thus, pressure will be four times of the initial pressure of the temperature is increased four times, while sustaining a constant volume.
