An acorn with a mass of 0.0300 kilograms falls from a tree. What is its kinetic energy when it reaches a velocity of 5.00 m/s? 1.47 J .075 J 0.375 J cannot be determined without knowing how far the acorn has fallen

Respuesta :

AL2006
KE = 1/2 m v^2.

That's 0.375 J.

Answer

Kinetic energy of acorn is 0.375 J .

Explanation:

Formula

Kinetic energy is defined by

[tex]K.E = \frac{1}{2}mv^{2}[/tex]

Where m is mass and v is velocity .

As given

An acorn with a mass of 0.0300 kilograms falls from a tree with a velocity of 5.00 m/s .

m = 0.0300 Kg

v = 5 m/s

Putting all the values in the formula

[tex]K.E = \frac{1}{2}\times 0.0300\times 5\times 5[/tex]

[tex]K.E = \frac{1\times 0.0300\times 5\times 5}{2}[/tex]

[tex]K.E = \frac{0.75}{2}[/tex]

K.E = 0.375 J

Therefore the kinetic energy of acorn is 0.375 J .