Express the limit as a definite integral on the given interval. lim n→∞ n xi ln(2 + xi2) δx, [0, 3] i = 1

Respuesta :

[tex]\displaystyle\lim_{n\to\infty}\sum_{i=1}^n x_i \ln(2+{x_i}^2)\,\Delta x=\int_0^3x\ln(2+x^2)\,\mathrm dx[/tex]

Answer:

The given expression is:

[tex]\lim_{n \to \infty} \sum x_{i}ln(2x+x_{i} ^{2}) \Delta x[/tex]

This expressions represent the sum of certain numbers of rectangles that comprehend the area under a curve, where the number of rectangles tend to infinite. Actually, this definition states that when [tex]n[/tex] tend to infinite, there's the area under the curve.

However, this can be expresses as a definite integral, which tend to have more sense for students:

[tex]\int\limits^3_0 {xln(2+x^{2})} \, dx[/tex]

With the integral form can be shown better what we tried to say before. The integral represents the area under the given function [tex]xln(2+x^{2})[/tex], but just the part inside the interval from 0 to 3. The limit also refers to this, but in a different notation.