Marcus plotted the points (0, 0), (6, 2), (18, 6) and (21, 7) on a graph. He wrote an equation for the relationship. Find another ordered pair that could be a solution of Marcus’s equitation. Justify your answer




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Respuesta :

From the point (0, 0), we know that the y-intercept is 0.
If we use the slope formula on the first two points:
[tex] \frac{2 - 0}{6 - 0} = \frac{2}{6} = \frac{1}{3} [/tex]
we get 1/3 as the slope.
Therefore, our equation in slope-intercept form is:
[tex]y = \frac{1}{3} x[/tex]
To find a point, we can plug in any x and solve for y, let's use x=1
[tex]y = \frac{1}{3} \times 12 = \frac{12}{3} = 4[/tex]
Therefore, our point is (12, 4)