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A worker pushes a wheelbarrow with a force of 40 n over a level distance of 6.0 m. if a frictional force of 24 n acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?

Respuesta :

HenryLCH
Net work done = 40*6 - 24 *6
=96 j

Answer:

对不起，我不知道对不起

Explanation:

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