Respuesta :
y - y1 = m(x - x1)
slope(m) = -5
(2,-6)....x1 = 2 and y1 = -6
sub
y - (-6) = -5(x - 2) =
y + 6 = -5(x - 2) <==== here is one
y + 6 = -5(x - 2)
y + 6 = -5x + 10
y = -5x + 10 - 6
y = -5x + 4 <=== here is another one
slope(m) = -5
(2,-6)....x1 = 2 and y1 = -6
sub
y - (-6) = -5(x - 2) =
y + 6 = -5(x - 2) <==== here is one
y + 6 = -5(x - 2)
y + 6 = -5x + 10
y = -5x + 10 - 6
y = -5x + 4 <=== here is another one
The equation that represents the line that has a slope of –5 and that passes through (2, –6) are :
y = -5x + 4
y + 6 = -5(x - 2)
Using linear equation formula,
y = mx + b
where
m = slope
b = y-intercept
Therefore,
m = -5
It passes through (2, -6)
y = -5x + b
let's find b
-6 = -5(2) + b
b = -6 + 10
b = 4
Therefore, the equation will be as follows:
- y = -5x + 4
it can be represented as (y - y₁) = m(x - x₁)
- y + 6 = -5(x - 2)
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