Answer:
p = 6.25 kg-m/s
Explanation:
It is given that,
Velocity of the baseball, v = 44.7 m/s
Weight of the baseball, W = 1.4 N
Firstly we need to find the mass of the baseball. It can be calculated as :
[tex]m=\dfrac{W}{g}[/tex]
[tex]m=\dfrac{1.4\ N}{9.8\ m/s^2}[/tex]
m = 0.14 kg
The momentum of an object is equal to the product of mass and velocity. It is given by :
[tex]p=m\times v[/tex]
[tex]p=0.14\ kg\times 44.7\ m/s[/tex]
p = 6.25 kg-m/s
So, the momentum it have when it hits the catcher is 6.25 kg-m/s. Hence, this is the required solution.
The amount of momentum the baseball has when it hits the catcher is 6.39 Kgm/s.
Given the following data:
We know that acceleration due to gravity (g) is equal to 10 meter per seconds square.
To find the amount of momentum the baseball has when it hits the catcher:
First of all, we would determine the mass of the baseball.
Mathematically, the weight of an object is given by the formula;
[tex]Weight = mg[/tex]
Where;
[tex]1.4 = mass \times 9.8\\\\Mass = \frac{1.4}{9.8}[/tex]
Mass = 0.1429 kg
Now, we can calculate the momentum the baseball:
Mathematically, momentum is given by the formula;
[tex]Momentum = mass \times velocity\\\\Momentum = 0.1429 \times 44.7[/tex]
Momentum = 6.39 Kgm/s
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