A system absorbs 52 joules of heat and does work using 25 joules of energy. What is the change in the internal energy of the system?

Respuesta :

The change in internal energy is [tex] \Delta U=Q+W [/tex]. Where [tex] \Delta U [/tex] is change in internal energy. [tex] Q [/tex] is heat added to the system (absorbed by the system). [tex] W [/tex] work done on the system. [tex] W [/tex] is taken as positive if work is done on the system and negative if work is done by the system. Here [tex] Q=52 [/tex] and [tex] W=-25 [/tex], hence change in internal energy is

[tex] \Delta U=52-25\\
\Delta U=27 [/tex]

Change in internal energy of the system is 27 J. Internal energy increases.

B. 27 joules is correct