The product of the given expression is -3ed + 3e^2 showing that they contain two terms and the product has a degree of 2
Equation are expressions separated by an equal sign.
Given the following expression
(–d + e)(4e + d).
We are to take the product of both expressions
Expand to have:
(–d + e)(4e + d) = -4ed - d^2 + 4e^2 + de
(–d + e)(4e + d) = -3ed + 3e^2
From the final answer, you can see that there are two terms in the solution and the product is degree 2
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