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PLEASE HELP! How many grams of water can be produced when 8.73 moles of benzene (C6H6) react with excess oxygen? Unbalanced equation: C6H6 + O2 → CO2 + H2O Show, or explain, all of your work along with the final answer.

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2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
2 moles C6H6 -------------------- 6 moles H2O8.73 moles C6H6 --------------- ( moles H2O)
( moles H2O) = 8.73 x 6 / 2
( moles H2O) = 52.38 / 2
= 26.19 moles of H2O
Molar mass H2O = 18.00 g/mol
1 mole -------------- 18.00 g26.19 moles ----- ( mass of H2O)
mass of H2O = 26. 19 x 18.00 => 471.42 g of water
hope this helps!


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