jorgepalacios90 jorgepalacios90

26-01-2018
Physics

contestada

A spring is stretched from equilibrium to 0.90 m and the work done on the spring equals 18j what is the value of the spring constant

Respuesta :

shariquekhan25ow696t shariquekhan25ow696t

26-01-2018

work done is given by 1/2kx^2
18 = 1/2*k*0.9*0.9
36 = k*0.81
44.4 = j/m^2

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