Respuesta :
Power = potential difference across resistance * current
P= i^2 * R
i = E/ equivalent resistance
Since all resistance are in series
Equivalent resistance = 8+12+28= 48
i = 24/48
i= 0.5
Power in R1= 0.5*0.5*8
= 2 watt
Power in R2= 0.5*0.5*12
= 3 watt
Power in R3= 0.5*0.5*28
= 7 watt
P= i^2 * R
i = E/ equivalent resistance
Since all resistance are in series
Equivalent resistance = 8+12+28= 48
i = 24/48
i= 0.5
Power in R1= 0.5*0.5*8
= 2 watt
Power in R2= 0.5*0.5*12
= 3 watt
Power in R3= 0.5*0.5*28
= 7 watt
Answer:
Power in R1 = 2 watts
Power in R2 = 3 watts
Power in R3 = 7 watts
Compute the total power delivered to the circuit by the 24-volt battery: 12 watts