Solution:
The height of the radio tower is 40.8 yd.
Explanation:
Let us draw a diagram for the given situation. In the attached diagram AB is the radio tower and Mia is standing at point C.
The angle of elevation is 11°. Hence, angle C is 11°.
Let the height of the tower is h.
In triangle ABC, we have
[tex]\tan \theta = \frac{AB}{BC} \\\\\tan 11^{\circ}=\frac{h}{210} \\\\h=210\tan 11^{\circ}\\\\h=40.8[/tex]
Therefore, the height of the radio tower is 40.8 yd.
