Respuesta :
The equation that shows the formation of chromium (ii) ion from neutral chromium atom is as follow
Cr ---> cr^2+ + 2e-
Cr^2+ is the chromium ion with oxidation state of two which is one of the common ion of chromium. Other common ion of chromium include chromium of oxidation state 6 and 3
Cr ---> cr^2+ + 2e-
Cr^2+ is the chromium ion with oxidation state of two which is one of the common ion of chromium. Other common ion of chromium include chromium of oxidation state 6 and 3
Answer : The balanced equation will be,
[tex]Cr\rightarrow Cr^{2+}+2e^-[/tex]
Explanation :
Oxidation : It is the process of losing of one or more electrons.
Reduction : It is the process of gaining of one or more electrons.
The balanced equation will be,
[tex]Cr\rightarrow Cr^{2+}+2e^-[/tex]
A neutral chromium atom is oxidized into chromium(II) ions by the loss of two electrons.