What is the length of line segment RS? Use the law of sines to find the answer. Round to the nearest tenth.

Answer:
Step-by-step explanation:
The law of sines is given by the formula;
[tex]\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}[/tex]
where A,B,C are the interior angles of triangle ABC and [tex]a,b,c[/tex] are the sides opposite these angles.
Applying the sine rule to ΔQRS, we obtain;
[tex]\frac{2.4}{\sin(S)} =\frac{3.1}{\sin(80\degree)}[/tex].
[tex]2.4\times \sin(80\degree) =3.1\sin(S)[/tex].
[tex]2.3635=3.1\sin(S)[/tex].
[tex]\Rightarrow \frac{2.3635}{3.1}=\sin(S)[/tex].
[tex]0.7624=\sin(S)[/tex].
[tex]\Rightarrow \sin^{-1}(0.7624)=S[/tex].
[tex]\Rightarrow 49.676=S[/tex].
The sum of angles in a triangle is 180 degrees.
[tex]<\:Q+49.676+80=180[/tex]
[tex]<\:Q=180-129.676[/tex]
[tex]\Rightarrow <\:Q=50.324[/tex]
We use the sine rule again
[tex]\frac{|RS|}{\sin(50.324\degree)}=\frac{3.1}{\sin(80\degree)}[/tex]
[tex]|RS|=\frac{3.1}{\sin(80\degree)}\times \sin(80\degree)[/tex]
[tex]|RS|=2.423[/tex]
To the nearest tenth
[tex]|RS|=2.4\:units[/tex]
Answer:
The length of segment RS is:
2.4 units.
Step-by-step explanation:
We will use the Law of Cosine to find the length of segment RS.
Let the segment RS be denoted by 'c'.
Let a=RQ=2.4 units.
b=QS=3.1 units.
Now, according to the law of cosine we have:
[tex]\dfrac{a}{\sin S}=\dfrac{b}{\sin R}=\dfrac{c}{\sin Q}\\\\i.e.\\\\\dfrac{2.4}{\sin S}=\dfrac{3.1}{\sin 80}=\dfrac{c}{\sin Q}[/tex]
On equating the first two equalities we have:
[tex]\dfrac{2.4}{\sin S}=\dfrac{3.1}{\sin 80}[/tex]
Hence, on solving we get:
S=49.68°
Now as we know that in a triangle the sum of all the angles of a triangle is:
180 degree.
Hence,
∠Q+∠R+∠S=180°
⇒ ∠Q+80°+49.68°=180°
⇒ ∠Q=50.32°
Similarly, on equating the second and third equality we have:
[tex]\dfrac{3.1}{\sin 80}=\dfrac{c}{\sin 50.32}\\\\\\This\ implies\ that:\\\\c=2.423[/tex]
Hence, the length of line segment is:
2.4 units.