The table of values represents a quadratic function.

What is the average rate of change for f(x) from x = 0 to x = 10 ?

x ​f(x)​
​−10​ 184
​−5​ 39
0 ​−6​
5 49
10 204

Respuesta :

(f(10) -f(0))/(10 -0) = (204 -(-6))/10 = 21

The average rate of change on the interval is 21.
aachen

The average rate of change for any function f(x) is the ratio of change in its y-values to change in its x-values for any two particular points on the curve of the function f(x). Mathematically, we can write it as follows :-

Average rate of change = [tex] \frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}} [/tex]

It says to find the average rate of change from x = 0 to x = 10.

From the given table, x = 0 corresponds to y = f(0) = -6 and x = 10 corresponds to y = f(10) = 204.

So we have two points A(0, -6) and B(10, 204).

Using the above formula, we can find average rate of change from A to B.

Average rate of change from (0, -6) to (10, 204) = [tex] \frac{204-(-6)}{10-0} =\frac{204+6}{10} = \frac{210}{10} =21 [/tex]

Hence, the final answer is 21.